设f,g都是<S,<sub>*</sub>>到的同态,并且*与*'运算均满足交换律和结合律,证明如下定义的函数h;s→s

设f,g都是<S,<sub>*</sub>>到<img src='https://img2.soutiyun.com/ask/2021-01-04/978611122517765.png' />的同态,并且*与*'运算均满足交换律和结合律,证明如下定义的函数h;s→s' h(x)=f(x)*'g(x)<img src='https://img2.soutiyun.com/ask/2021-01-04/978611229831903.png' />的同态.

时间:2024-04-03 14:06:36

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