In "A Painful Case", what does "gallery of pleasure" mean（）

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• Do you find getting up in the morning so difficult that it's painful？ This might be called laziness, but Dr. Kleitman has a new explanation. He has proved everyone has a daily energy cycle.

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• 70、以下程序的功能是根据输入的“y”或“Y”与“n”或“N“，在屏幕上分别显示出“ This is YES.”与 “ This is NO.”,按要求在空白处填写适当的表达式或语句，使程序完整并符合题目要求。 include ＜stdio.h＞ void YesNo（char ch) { switch （ch) { case 'y': case 'Y': printf（"This is YES. \n"); ______________; case 'n': case 'N': printf（"This is NO. \n"); } } int main（) { char ch; printf（"\nEnter a char 'y', 'Y' or 'n', 'N': "); ch = _______________; printf（"ch: % c", ch); ____________;

  A．第10行： break 第22行： getchar() 第25行： YesNo(ch) B．第10行： continue 第22行： getchar() 第25行： YesNo() C．第10行： continue 第22行： scanf("%c",&c) 第25行： YesNo(ch) D．第10行： break 第22行： scanf("%c",&c) 第25行： YesNo()

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• 有以下程序：includ＜stdio.h＞voifun（ina,inb）int;t=a;a=b;b=t;}main（）inc[10]={1,2,3,4,5,6,7,8,9,0},i;for（i=0;i＜10;i+=2）fun（c[i],c[i+1]）;for（i=0;i＜10;i++）printf（"%d,",c[i]）;printf（&quot&qu

  A．1，2，3，4，5，6，7，8，9，0 B．2，1，4，3，6，5，8，7，0，9 C．0，9，8，7，6，5，4，3，2，1 D．0，1，2，3，4，5，6，7，8，9

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• For a theory to be useful, it must be confirmed in each test case.（)

  是 否

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• Oneoftheusecasesinyourwebapplicationusesmanysession-scopedattributes.Attheendoftheusecase，youwanttoclearoutthissetofattributesfromthesessionobject.Assumethatthisstaticvariableholdsthissetofattributenames：201.privatestaticfinalSet＜String＞USE_CASE_ATTRS；202.static{203.USE_CASE_ATTRS.add（"customerOID"）；204.USE_CASE_ATTRS.add（"custMgrBean"）；205.USE_CASE_ATTRS.add（"orderOID"）；206.USE_CASE_ATTRS.add（"orderMgrBean"）；207.}Whichcodesnippetdeletestheseattributesfromthesessionobject？（）

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• He gave us a specific statement of the case in question（）

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• 2、有如下程序 main0 { int x=1,a=0,b=0; switch（x){ case 0: b++; case 1: a++ case 2: a++;b++ } printf（"a=%d,b=%d\n",a,b); } 该程序的输出结果是

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• 8、下面程序段，显示的结果是 。 Dim x% x = Int（Rnd) + 5 Select Case x Case 5 MsgBox（"优秀") Case 4 MsgBox（"良好") Case 3 MsgBox（"通过") Case Else MsgBox（"不通过") End Select

  A．优秀 B．良好 C．通过 D．不通过 E．不确定，随机

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• 下列程序段的输出结果为（）。int a=2；switch（a)case 2：System.out.print（"Value is 2．")；case 3：System.out.println（"Value is 3.")；break；default：System.out.prinfln（"end")；break；

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