Fifty cases of Green Tea you sent us were found to be badly damaged. This was apparently attributable to()packing.
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would you like()a cup of tea?
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Fifty bags melted due to()of the cargo.
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Chinese green tea called Tieguanyin, which costs $3, 000 per ________, approximately $15 for a single cup.
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The number of ________ in our class ________ fifty.
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有如下程序段: int x=1,y=1; int m,n; m=n=1; switch (m) { case 0:x=x*2; case 1: { switch (n) { case1:x=x*2; case2:y=y*2;break; case 3:x++; } } case 2: x++;y++; case 3: x*=2;y*=2;break; default: x++;y++; } 执行完成后,x和y的值分别是_____。
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下列语句序列执行后,k 的值是( )。 int x = 6, y = 10, k = 5; switch (x % y) { case 0: k = x * y; case 6: k = x / y; case 12: k = x - y; default: k = x * y - x; }
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Chinese green tea called Tieguanyin, which costs $3, 000 per ________, approximately $15 for a single cup.
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Chinese tea can be divided into six groups: green, __________, yellow, white, dark, and oolong.
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As a type of green tea, Longjing tea its green color, delicate aroma, mellow taste and beautiful shape.
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有如下程序: Private Sub Command1_Click() x = InputBox(\input value\) Select Case x Case Is > 0 y = x + 3 Case Is = 0 y = x + 2 Case Else y = x + 1 End Select Print x; y End Sub 假设运行时从键盘上输入-8,输出结果是(______)。
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Fuding, where a large-leaf variety of tea trees is grown, was considered as the origin of black tea.
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1.Our Green Tea is customarily packed ______ standard boxes, boxes to a carton.
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3 Good tea sets can guarantee the good taste of the tea.
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— What would you like to drink? — ________, please. [ ] A. Two cup of tea B. Two cups tea C. Two cups of tea D. Two cups of teas
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有如下程序 x=InputBox("input value of x") Select Case x CaseIs>0y=y+1 CaseIs=0y=x+2 Case E
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运行下列程序: x=InputBox("input value of x") Select Case X CaseIs>0 y=y+1 CaseIs=0 y=x+2 C
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Express I(X;Y)in term of α and interpret the special case α=1.
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3、下面程序段运行后,z的值是 。 Dim x,y,z As Integer x = 3 : y = -1 Select Case x+y Case 1 z = 80 Case -1 z = 70 Case Else z = 60 End Select
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若有定义“intx=1,y=1,m=1,n=1;”,则执行下列语句后,变量x和y的值分别是()。switch(m)/{case0:x=x*2;case1:switch(n)/{case1:x=x*2;case2:y=y*2;break;case3:x++;/}case2:x++;y++;case3:x*=2;y*=2;break;default:x++;y++;/}}
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写出下面程序的输出结果includeint main(){int x=1, y=0, a=0, b=0;switch(x){case 1:switch(y){case 0: a++;case 1: b++;}case 2: a++;b++;}printf(“a=%d, b=%d
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