1、若f(x)<0成立,则g(x)≤0必须成立;若f(x)<0不成立,则g(x)无限制。引入一个0-1变量y来解决这一逻辑关系:

A.f(x)≥-M(1-y) g(x)≤My B.f(x)≥-My g(x)≤My C.f(x)≥-M(1-y) g(x)≤M(1-y) D.g(x)≥-M(1-y) f(x)≤My

时间:2023-12-30 09:33:35

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