设函数f(x)在[a,b]上连续,a≤x<sub>1</sub><x<sub>2</sub><...<x<sub>n</sub>≤b,证明在[a,b]中必有ξ,使得

设函数f(x)在[a,b]上连续,a≤x<sub>1</sub><x<sub>2</sub><...<x<sub>n</sub>≤b,证明在[a,b]中必有ξ,使得 <img src='https://img2.soutiyun.com/ask/2020-12-15/976895957488208.png' />

时间:2024-04-03 14:33:52

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