若环R适合:a∈R,a<sup>2</sup>=a,证明:(1)a∈R,a+a=0 (2)R是交换环

若环R适合:<img src='https://img2.soutiyun.com/ask/2021-02-26/983200799666388.png' />a∈R,a<sup>2</sup>=a,证明: (1)<img src='https://img2.soutiyun.com/ask/2021-02-26/983200799666388.png' />a∈R,a+a=0 (2)R是交换环

时间:2024-04-09 13:23:25

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